Solve for xxx in the equation: log2(x2−1)−log2(x+1)=2\log_2(x^2 - 1) - \log_2(x + 1) = 2log2(x2−1)−log2(x+1)=2.
x=3x = 3x=3
x=5x = 5x=5
x=−5x = -5x=−5
x=4x = 4x=4