Solve for xxx in the inequality x2−3x−10x+1≤0\frac{x^2 - 3x - 10}{x + 1} \leq 0x+1x2−3x−10≤0.
(−∞,−2]∪[5,∞)(-\infty, -2] \cup [5, \infty)(−∞,−2]∪[5,∞)
(−∞,−1)∪[−2,5](-\infty, -1) \cup [-2, 5](−∞,−1)∪[−2,5]
(−∞,−2]∪(−1,5](-\infty, -2] \cup (-1, 5](−∞,−2]∪(−1,5]
[−2,−1)∪[5,∞)[-2, -1) \cup [5, \infty)[−2,−1)∪[5,∞)