Solve for xxx: 2x−3+2=x\sqrt{2x - 3} + 2 = x2x−3+2=x
x=3+2x = 3 + \sqrt{2}x=3+2 only
x=3−2x = 3 - \sqrt{2}x=3−2 only
x=3+2x = 3 + \sqrt{2}x=3+2 and x=3−2x = 3 - \sqrt{2}x=3−2
No real solutions