Solve for xxx: x2−13=2\sqrt[3]{x^2 - 1} = 23x2−1=2.
x=±3x = \pm 3x=±3
x=±9x = \pm 9x=±9
x=±7x = \pm \sqrt{7}x=±7
x=±3x = \pm \sqrt{3}x=±3