Solve for xxx: x3−9x≥0x^3 - 9x \geq 0x3−9x≥0.
[−3,0]∪[3,∞)[-3, 0] \cup [3, \infty)[−3,0]∪[3,∞)
(−∞,−3]∪[0,3](-\infty, -3] \cup [0, 3](−∞,−3]∪[0,3]
[−3,3][-3, 3][−3,3]
[0,3][0, 3][0,3]