Solve for yyy in terms of xxx: 2x+3y=122x + 3y = 122x+3y=12.
y=12−2xy = 12 - 2xy=12−2x
y=12−2x3y = \frac{12 - 2x}{3}y=312−2x
y=123−2xy = \frac{12}{3} - 2xy=312−2x
y=2x−123y = \frac{2x - 12}{3}y=32x−12