Solve dydx=e3x\frac{dy}{dx} = e^{3x}dxdy=e3x with the condition y(0)=0y(0) = 0y(0)=0.
y=13e3x−13y = \frac{1}{3}e^{3x} - \frac{1}{3}y=31e3x−31
y=e3x−1y = e^{3x} - 1y=e3x−1
y=13e3xy = \frac{1}{3}e^{3x}y=31e3x
y=3e3x−3y = 3e^{3x} - 3y=3e3x−3