Solve dydx=(x+y−2)2\frac{dy}{dx} = (x+y-2)^2dxdy=(x+y−2)2 with y(0)=2y(0)=2y(0)=2 using v=x+y−2v = x+y-2v=x+y−2. What is the solution y(x)y(x)y(x)?
y=2+tan(x)y = 2 + \tan(x)y=2+tan(x)
y=2−tan(x)y = 2 - \tan(x)y=2−tan(x)
y=2+11−xy = 2 + \frac{1}{1-x}y=2+1−x1
y=2+xy = 2 + xy=2+x