Solve: log2(x+1)+log2(x−1)=3\log_{2}(x+1) + \log_{2}(x-1) = 3log2(x+1)+log2(x−1)=3.
x=3x = 3x=3
x=7x = \sqrt{7}x=7
x=−3,3x = -3, 3x=−3,3
x=4x = 4x=4