Solve the absolute value equation: ∣x−3∣=2∣x−1∣|x - 3| = 2|x - 1|∣x−3∣=2∣x−1∣
x=1x = 1x=1 only
x=5x = 5x=5 only
x=1x = 1x=1 and x=5x = 5x=5
x=−1x = -1x=−1 and x=5x = 5x=5