Solve the Bernoulli equation dzdx+zx=z2x3\frac{dz}{dx} + \frac{z}{x} = z^2 x^3dxdz+xz=z2x3 for x>0x > 0x>0. What is the general solution?
z(x)=1cx−x4z(x) = \frac{1}{cx - x^4}z(x)=cx−x41
z(x)=1x(c−x4)z(x) = \frac{1}{x(c - x^4)}z(x)=x(c−x4)1
z(x)=1x3(c−x)z(x) = \frac{1}{x^3(c - x)}z(x)=x3(c−x)1
z(x)=cx−x3z(x) = \frac{c}{x} - x^3z(x)=xc−x3