Solve the inequality: x2−4x+3≥0\frac{x^2 - 4}{x + 3} \geq 0x+3x2−4≥0
(−3,−2]∪[2,∞)(-3, -2] \cup [2, \infty)(−3,−2]∪[2,∞)
(−∞,−3]∪[−2,2](-\infty, -3] \cup [-2, 2](−∞,−3]∪[−2,2]
[−3,−2]∪[2,∞)[-3, -2] \cup [2, \infty)[−3,−2]∪[2,∞)
(−∞,−3)∪[−2,2](-\infty, -3) \cup [-2, 2](−∞,−3)∪[−2,2]