Solve the inequality x2−16<3\sqrt{x^2 - 16} < 3x2−16<3.
x∈(−5,5)x \in (-5, 5)x∈(−5,5)
x∈(−4,4)x \in (-4, 4)x∈(−4,4)
x∈(−5,−4]∪[4,5]x \in (-5, -4] \cup [4, 5]x∈(−5,−4]∪[4,5]
x∈(−5,−4]∪[4,5)x \in (-5, -4] \cup [4, 5)x∈(−5,−4]∪[4,5)