Solve the rational inequality x+2x−3≤0\frac{x+2}{x-3} \leq 0x−3x+2≤0.
(−2,3)(-2, 3)(−2,3)
[−2,3)[-2, 3)[−2,3)
(−∞,−2]∪(3,∞)(-\infty, -2] \cup (3, \infty)(−∞,−2]∪(3,∞)
(−2,3](-2, 3](−2,3]