Solve the system {xy=12x+y=8\begin{cases} xy = 12 \\ x + y = 8 \end{cases}{xy=12x+y=8 where x,yx, yx,y are real numbers. Which statement is TRUE?
The system has no real solutions.
The system has exactly one real solution: (x,y)=(6,2)(x, y) = (6, 2)(x,y)=(6,2).
The system has two real solutions: (6,2)(6, 2)(6,2) and (2,6)(2, 6)(2,6).
The system has infinitely many real solutions.