Solve ∣x2−1∣<3|x^2 - 1| < 3∣x2−1∣<3.
−2<x<2-2 < x < 2−2<x<2 and x≠0x \neq 0x=0
x∈(−2,2)x \in (-2, 2)x∈(−2,2) excluding roots
x∈(−2,2)x \in (-2, 2)x∈(−2,2)
−2<x<2-2 < x < 2−2<x<2