Solve: x2−16≤0x^2 - 16 \leq 0x2−16≤0.
x≤−4x \leq -4x≤−4 or x≥4x \geq 4x≥4
x≥−4x \geq -4x≥−4
x≤4x \leq 4x≤4
−4≤x≤4-4 \leq x \leq 4−4≤x≤4