Solve ∣x2−2∣=1|x^2 - 2| = 1∣x2−2∣=1.
x=±1,±3x = \pm 1, \pm \sqrt{3}x=±1,±3
x=±1x = \pm 1x=±1
x=±3x = \pm \sqrt{3}x=±3
x=1,3x = 1, 3x=1,3