Solve: ∣x2−3∣<1|x^2 - 3| < 1∣x2−3∣<1.
−2<x<−2-2 < x < -\sqrt{2}−2<x<−2 or 2<x<2\sqrt{2} < x < 22<x<2
−2<x<2-\sqrt{2} < x < \sqrt{2}−2<x<2
−2<x<2-2 < x < 2−2<x<2
x<2x < 2x<2