Solve y′=cos(x)e−yy' = \cos(x)e^{-y}y′=cos(x)e−y with y(0)=0y(0) = 0y(0)=0.
y=sin(x)y = \sin(x)y=sin(x)
ey=cos(x)+1e^y = \cos(x) + 1ey=cos(x)+1
ey=sin(x)+1e^y = \sin(x) + 1ey=sin(x)+1
ey=sin(x)e^y = \sin(x)ey=sin(x)