Solve y′=eyxy' = \frac{e^y}{x}y′=xey.
−e−y=ln∣x∣+C-e^{-y} = \ln|x| + C−e−y=ln∣x∣+C
ey=ln∣x∣+Ce^y = \ln|x| + Cey=ln∣x∣+C
e−y=x+Ce^{-y} = x + Ce−y=x+C
−ey=1x+C-e^y = \frac{1}{x} + C−ey=x1+C