Subtract: 4xx2−16−1x−4\frac{4x}{x^2-16} - \frac{1}{x-4}x2−164x−x−41.
3x+4x2−16\frac{3x+4}{x^2-16}x2−163x+4
5x−4x2−16\frac{5x-4}{x^2-16}x2−165x−4
3x−4x2−16\frac{3x-4}{x^2-16}x2−163x−4
1x+4\frac{1}{x+4}x+41