The CDF of a continuous random variable XXX is F(x)={0x<0x240≤x≤21x>2F(x) = \begin{cases} 0 & x < 0 \\ \frac{x^2}{4} & 0 \le x \le 2 \\ 1 & x > 2 \end{cases}F(x)=⎩⎨⎧04x21x<00≤x≤2x>2. Find P(X≤1)P(X \le 1)P(X≤1).
12\frac{1}{2}21
14\frac{1}{4}41
34\frac{3}{4}43
18\frac{1}{8}81