The center of the circle x2+y2−4x+6y−12=0x^2 + y^2 - 4x + 6y - 12 = 0x2+y2−4x+6y−12=0 is:
(2,−3)(2, -3)(2,−3)
(−2,3)(-2, 3)(−2,3)
(4,−6)(4, -6)(4,−6)
(−4,6)(-4, 6)(−4,6)