Guest Session: 1 Question Remaining. Create Account to save progress.
Login
Circles & Conicseasy
0:00.0

The distance from the center to a vertex of an ellipse fracx2a2+fracy2b2=1\\frac{x^2}{a^2} + \\frac{y^2}{b^2} = 1fracx2a2+fracy2b2=1 (where a>ba > ba>b) is: