Ononot — The fundamental solution to x^2 - 3y^2 = 1 is (2, 1). Using

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Diophantine Equationsmedium

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The fundamental solution to $x^2 - 3y^2 = 1$ is $(2, 1)$ . Using the Brahmagupta-Fibonacci identity $(x_1^2 - 3y_1^2)(x_2^2 - 3y_2^2) = (x_1x_2 + 3y_1y_2)^2 - 3(x_1y_2 + y_1x_2)^2$ , the next solution is obtained by composing $(2,1)$ with itself. What is this next solution $(x_2, y_2)$ ?