The recurrence fn=fn−1+22f_n = f_{n-1} + 22fn=fn−1+22 with f1=19f_1 = 19f1=19 gives fn=19+(n−1)cdot22f_n = 19 + (n-1) \\cdot 22fn=19+(n−1)cdot22. What is f6f_6f6?
132132132
110110110
129129129
117117117