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Units & Conversionshard
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The thermal conductivity kkk is 0.5 W/(m⋅K)0.5 \text{ W/(m} \cdot \text{K)}0.5 W/(m⋅K). Calculate its value in Btu⋅in/(hr⋅ft2⋅∘F)\text{Btu} \cdot \text{in} / (\text{hr} \cdot \text{ft}^2 \cdot ^\circ\text{F})Btu⋅in/(hr⋅ft2⋅∘F). (Approximation: 1 W/mK≈6.933 Btu⋅in/(hr⋅ft2⋅∘F)1 \text{ W/mK} \approx 6.933 \text{ Btu} \cdot \text{in} / (\text{hr} \cdot \text{ft}^2 \cdot ^\circ\text{F})1 W/mK≈6.933 Btu⋅in/(hr⋅ft2⋅∘F))