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Conditional Probabilityeasy
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Two events EEE and FFF have P(E∪F)=0.8P(E \cup F) = 0.8P(E∪F)=0.8, P(E)=0.5P(E) = 0.5P(E)=0.5, and P(F)=0.4P(F) = 0.4P(F)=0.4. Find P(E∣F)P(E|F)P(E∣F).