Two events XXX and YYY have P(X)=0.4P(X) = 0.4P(X)=0.4, P(Y)=0.6P(Y) = 0.6P(Y)=0.6, and P(X∩Y)=0.2P(X \cap Y) = 0.2P(X∩Y)=0.2. What is P(Xc∣Y)P(X^c | Y)P(Xc∣Y)?
\frac{2}{3}
\frac{1}{3}
\frac{0.4}{0.6}
\frac{0.4}{0.2}