Two independent events P and Q: P(P)=0.6P(P)=0.6P(P)=0.6, P(Q)=0.4P(Q)=0.4P(Q)=0.4. Find P(P∪Q)P(P \cup Q)P(P∪Q).
(0.6)(0.4)=0.24(0.6)(0.4) = 0.24(0.6)(0.4)=0.24
1−(0.4)(0.6)=0.761 - (0.4)(0.6) = 0.761−(0.4)(0.6)=0.76
0.6+0.4=1.00.6 + 0.4 = 1.00.6+0.4=1.0
0.6×0.4=0.240.6 \times 0.4 = 0.240.6×0.4=0.24