Use Newton's method starting at x0=2x_0 = 2x0=2 to approximate a root of f(x)=x2−5f(x) = x^2 - 5f(x)=x2−5. What is x1x_1x1?
x1=94=2.25x_1 = \frac{9}{4} = 2.25x1=49=2.25
x1=2.5x_1 = 2.5x1=2.5
x1=5x_1 = \sqrt{5}x1=5
x1=1.9x_1 = 1.9x1=1.9