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Power Seriesmedium
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Use the alternating series error bound to estimate the error when approximating ln⁡(1.1)\ln(1.1)ln(1.1) using the first 3 terms of ln⁡(1+x)=x−x22+x33−x44+⋯\ln(1+x) = x - \frac{x^2}{2} + \frac{x^3}{3} - \frac{x^4}{4} + \cdotsln(1+x)=x−2x2​+3x3​−4x4​+⋯ at x=0.1x = 0.1x=0.1.