Use the Factor Theorem to show that (x−1)(x - 1)(x−1) is a factor of x100−1x^{100} - 1x100−1.
Only if 100 is even
Cannot be determined without full expansion
No, since 1100≠01^{100} \neq 01100=0
Yes, since P(1)=1−1=0P(1) = 1 - 1 = 0P(1)=1−1=0