Verify: does z=2ei5π/6z = 2e^{i5\pi/6}z=2ei5π/6 have a negative real part?
Yes, Re(z)=−3\text{Re}(z) = -\sqrt{3}Re(z)=−3
No, Re(z)=1\text{Re}(z) = 1Re(z)=1
No, Re(z)=3\text{Re}(z) = \sqrt{3}Re(z)=3
Yes, Re(z)=−1\text{Re}(z) = -1Re(z)=−1