What is the center of the circle (x+1)2+(y−4)2=16(x + 1)^2 + (y - 4)^2 = 16(x+1)2+(y−4)2=16?
(−1,4)(-1, 4)(−1,4)
(1,−4)(1, -4)(1,−4)
(−1,−4)(-1, -4)(−1,−4)
(1,4)(1, 4)(1,4)