What is the domain of g(x)=\acx+1x2−9g(x) = \ac{x+1}{x^2 - 9}g(x)=\acx+1x2−9?
x≠3x \neq 3x=3 and x≠−3x \neq -3x=−3
x≠3x \neq 3x=3
x>3x > 3x>3
All real numbers