What is the equation of the circle with diameter endpoints (1,2)(1, 2)(1,2) and (7,8)(7, 8)(7,8)?
(x−4)2+(y−5)2=36(x-4)^2 + (y-5)^2 = 36(x−4)2+(y−5)2=36
(x−4)2+(y−5)2=72(x-4)^2 + (y-5)^2 = 72(x−4)2+(y−5)2=72
(x−4)2+(y−5)2=18(x-4)^2 + (y-5)^2 = 18(x−4)2+(y−5)2=18
(x−4)2+(y−5)2=9(x-4)^2 + (y-5)^2 = 9(x−4)2+(y−5)2=9