What is the general solution for an=4an−1−4an−2+3a_n = 4a_{n-1} - 4a_{n-2} + 3an=4an−1−4an−2+3?
c12n+c2n2n+3c_1 2^n + c_2 n 2^n + 3c12n+c2n2n+3
c12n+c2n2n+1c_1 2^n + c_2 n 2^n + 1c12n+c2n2n+1
c12n+c2n2n+1/3c_1 2^n + c_2 n 2^n + 1/3c12n+c2n2n+1/3
c12n+c2n2n+3nc_1 2^n + c_2 n 2^n + 3nc12n+c2n2n+3n