What is the general solution for y′=cos(x+y)y' = \cos(x+y)y′=cos(x+y)?
tan(x+y2)=x+C\tan(\frac{x+y}{2}) = x + Ctan(2x+y)=x+C
cot(x+y2)=x+C\cot(\frac{x+y}{2}) = x + Ccot(2x+y)=x+C
tan(x+y2)=x+C\tan(\frac{x+y}{2}) = x + Ctan(2x+y)=x+C is not correct
sin(x+y)=x+C\sin(x+y) = x + Csin(x+y)=x+C