What is the general solution of y′′+2y′+y=0y'' + 2y' + y = 0y′′+2y′+y=0?
y=c1e−2x+c2e−xy = c_1e^{-2x} + c_2e^{-x}y=c1e−2x+c2e−x
y=c1e−x+c2exy = c_1e^{-x} + c_2e^xy=c1e−x+c2ex
y=(c1+c2x)exy = (c_1 + c_2x)e^xy=(c1+c2x)ex
y=(c1+c2x)e−xy = (c_1 + c_2x)e^{-x}y=(c1+c2x)e−x