What is the inverse of f(x)=3x+12f(x) = \frac{3x + 1}{2}f(x)=23x+1?
f−1(x)=2x−13f^{-1}(x) = \frac{2x - 1}{3}f−1(x)=32x−1
f−1(x)=2x+13f^{-1}(x) = \frac{2x + 1}{3}f−1(x)=32x+1
f−1(x)=23x+1f^{-1}(x) = \frac{2}{3x + 1}f−1(x)=3x+12
f−1(x)=3x−21f^{-1}(x) = \frac{3x - 2}{1}f−1(x)=13x−2