What is the nnnth term of the geometric sequence 2,8,32,128,…2, 8, 32, 128, \ldots2,8,32,128,…?
22n−12^{2n-1}22n−1
4n−14^{n-1}4n−1
2⋅4n2 \cdot 4^n2⋅4n
4n4^n4n