What is the vertex of the parabola y=3(x−2)2+1y = 3(x-2)^2 + 1y=3(x−2)2+1?
(2,1)(2, 1)(2,1)
(−2,1)(-2, 1)(−2,1)
(2,−1)(2, -1)(2,−1)
(−2,−1)(-2, -1)(−2,−1)