Which condition makes an IVP y′=f(x,y)y' = f(x, y)y′=f(x,y) solvable for a unique solution?
y(0) must be 0.
f(x, y) and ∂f∂y\frac{\partial f}{\partial y}∂y∂f must be continuous in a region containing (x0,y0)(x_0, y_0)(x0,y0).
The ODE must be second-order.
f(x, y) must be constant.