Which expression is the result of applying separation of variables to dydx=−3y\frac{dy}{dx} = -3ydxdy=−3y?
∫1ydy=∫−3dx\int \frac{1}{y} dy = \int -3 dx∫y1dy=∫−3dx
∫ydy=∫−3dx\int y dy = \int -3 dx∫ydy=∫−3dx
∫−3ydy=∫1dx\int -3y dy = \int 1 dx∫−3ydy=∫1dx
∫13ydy=∫xdx\int \frac{1}{3y} dy = \int x dx∫3y1dy=∫xdx