Which expression represents the integral of f(y)=3y2+4f(y) = 3y^2 + 4f(y)=3y2+4 from y=−1y = -1y=−1 to y=1y = 1y=1?
∫1−1(3y2+4)dy\int_1^{-1} (3y^2 + 4) dy∫1−1(3y2+4)dy
∫−11(3y2+4)dy\int_{-1}^1 (3y^2 + 4) dy∫−11(3y2+4)dy
∫01(3y2+4)dy\int_0^1 (3y^2 + 4) dy∫01(3y2+4)dy
[y3+4y]−11[y^3 + 4y]_{-1}^1[y3+4y]−11