Which expression represents the Law of Sines in △ABC\triangle ABC△ABC?
sin2A+cos2A=1\sin^2 A + \cos^2 A = 1sin2A+cos2A=1
tanA=sinAcosA\tan A = \frac{\sin A}{\cos A}tanA=cosAsinA
sinAa=sinBb=sinCc\frac{\sin A}{a} = \frac{\sin B}{b} = \frac{\sin C}{c}asinA=bsinB=csinC
a2=b2+c2−2bccosAa^2 = b^2 + c^2 - 2bc\cos Aa2=b2+c2−2bccosA