Which interval represents the solution to ∣x2−4x+3∣<1|x^2 - 4x + 3| < 1∣x2−4x+3∣<1?
(2−2,2+2)(2-\sqrt{2}, 2+\sqrt{2})(2−2,2+2)
(2−2,1)∪(3,2+2)(2-\sqrt{2}, 1) \cup (3, 2+\sqrt{2})(2−2,1)∪(3,2+2)
(1,3)(1, 3)(1,3)
(0,4)(0, 4)(0,4)