Which of the following is correct for the solution of ∣x+1∣≤2|x + 1| \leq 2∣x+1∣≤2?
−3≤x≤−1-3 \leq x \leq -1−3≤x≤−1
−1≤x≤3-1 \leq x \leq 3−1≤x≤3
1≤x≤31 \leq x \leq 31≤x≤3
−3≤x≤1-3 \leq x \leq 1−3≤x≤1